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Define the concept of a limit. Lim 𝑥→1 4𝑥3−2𝑥2+𝑥−3 𝑥−1 = 4(1)3−2(1)2+1−3 1−1 = 0 0 the value of the limit is indeterminate using substitution. − 5 + x 5 x = ________ y x.
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We'll Also Work On Determining Limits Algebraically.
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Now, Factor And Simplify The Limit.
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